is a town located in Broward County, Florida
. As of the 2000
census, the town had a total population of 3,416.
Geography\nBroward Estates is located at 26°7'31" North, 80°11'48" West (26.125404, -80.196559)1
According to the United States Census Bureau
, the town has a total area of 1.3 km²
). 1.3 km² (0.5 mi²) of it is land and none of it is covered by water.
Demographics\nAs of the census
, there are 3,416 people, 993 households, and 831 families residing in the town. The population density
is 2,536.4/km² (6,611.4/mi²). There are 1,025 housing units at an average density of 761.1/km² (1,983.8/mi²). The racial makeup of the town is 0.82% White, 96.96% African American
, 0.03% Native American
, 0.29% Asian
, 0.00% Pacific Islander, 0.32% from other races, and 1.58% from two or more races. 1.23% of the population are Hispanic
of any race.
There are 993 households out of which 28.6% have children under the age of 18 living with them, 43.1% are married couples living together, 32.6% have a female householder with no husband present, and 16.3% are non-families. 12.3% of all households are made up of individuals and 4.3% have someone living alone who is 65 years of age or older. The average household size is 3.43 and the average family size is 3.70.
In the town the population is spread out with 31.7% under the age of 18, 7.6% from 18 to 24, 24.2% from 25 to 44, 25.4% from 45 to 64, and 11.1% who are 65 years of age or older. The median age is 34 years. For every 100 females there are 87.6 males. For every 100 females age 18 and over, there are 82.7 males.
The median income for a household in the town is $37,298, and the median income for a family is $38,712. Males have a median income of $26,726 versus $24,360 for females. The per capita income for the town is $12,471. 23.2% of the population and 23.3% of families are below the poverty line. Out of the total people living in poverty, 28.9% are under the age of 18 and 25.5% are 65 or older.