Lac du Flambeau is a town located in Vilas County, Wisconsin. As of the 2000 census, the town had a total population of 3,004.

Geography

\nAccording to the
United States Census Bureau, the town has a total area of 330.8 km² (127.7 mi²). 259.8 km² (100.3 mi²) of it is land and 71.0 km² (27.4 mi²) of it is water. The total area is 21.45% water.

Demographics

\nAs of the
census of 2000, there are 3,004 people, 1,093 households, and 821 families residing in the town. The population density is 11.6/km² (29.9/mi²). There are 2,981 housing units at an average density of 11.5 persons/km² (29.7 persons/mi²). The racial makeup of the town is 39.55% White, 0.20% African American, 59.39% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.30% from other races, and 0.57% from two or more races. 1.60% of the population are Hispanic or Latino of any race. There are 1,093 households out of which 31.7% have children under the age of 18 living with them, 49.2% are married couples living together, 19.3% have a woman whose husband does not live with her, and 24.8% are non-families. 20.1% of all households are made up of individuals and 8.1% have someone living alone who is 65 years of age or older. The average household size is 2.72 and the average family size is 3.07. In the town the population is spread out with 29.8% under the age of 18, 7.1% from 18 to 24, 23.0% from 25 to 44, 23.4% from 45 to 64, and 16.8% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 99.1 males. For every 100 females age 18 and over, there are 90.6 males. The median income for a household in the town is $30,349, and the median income for a family is $33,036. Males have a median income of $27,589 versus $22,560 for females. The per capita income for the town is $15,176. 15.7% of the population and 12.1% of families are below the poverty line. Out of the total people living in poverty, 24.1% are under the age of 18 and 5.0% are 65 or older.