Pembroke Park is a town located in Broward County, Florida. As of the 2000 census, the town had a total population of 6,299.


\nPembroke Park is located at 25°59'4" North, 80°10'38" West (25.984326, -80.177305)
1. According to the United States Census Bureau, the town has a total area of 4.6 km² (1.8 mi²). 3.7 km² (1.4 mi²) of it is land and 0.9 km² (0.4 mi²) of it is water. The total area is 20.22% water.


\nAs of the
census of 2000, there are 6,299 people, 2,742 households, and 1,595 families residing in the town. The population density is 1,724.9/km² (4,465.6/mi²). There are 4,406 housing units at an average density of 1,206.5/km² (3,123.6/mi²). The racial makeup of the town is 42.61% White, 48.98% African American, 0.37% Native American, 0.68% Asian, 0.06% Pacific Islander, 3.95% from other races, and 3.35% from two or more races. 15.35% of the population are Hispanic or Latino of any race. There are 2,742 households out of which 29.5% have children under the age of 18 living with them, 31.8% are married couples living together, 21.6% have a female householder with no husband present, and 41.8% are non-families. 33.7% of all households are made up of individuals and 15.1% have someone living alone who is 65 years of age or older. The average household size is 2.29 and the average family size is 2.96. In the town the population is spread out with 27.0% under the age of 18, 9.0% from 18 to 24, 28.0% from 25 to 44, 18.7% from 45 to 64, and 17.4% who are 65 years of age or older. The median age is 33 years. For every 100 females there are 85.4 males. For every 100 females age 18 and over, there are 79.3 males. The median income for a household in the town is $22,605, and the median income for a family is $25,972. Males have a median income of $26,275 versus $21,230 for females. The per capita income for the town is $14,369. 24.0% of the population and 20.0% of families are below the poverty line. Out of the total people living in poverty, 27.2% are under the age of 18 and 25.5% are 65 or older.